Thread: Integral of arbitary powers

the integral b=1, a=0 of (1/2)[(a^x-a^-x)/(a^x+a^-x)]

Originally Posted by akhayoon

the integral b=1, a=0 of (1/2)[(a^x-a^-x)/(a^x+a^-x)]

do you mean ?

using a for the limits and then a again for the constants in the integral is confusing. be specific and clear

if that is your integral, use the substitution

after the substitution will the new bounds be

?

which then leads to

? with those bounds I mentioned of course

Originally Posted by akhayoon

after the substitution will the new bounds be

?

which then leads to

? with those bounds I mentioned of course

yes, that's one way to do it. or, you could switch back to a function of x and use the old limits if you like.