Just need a couple of problems double checked for me. lim (x^2+4x-5)/x^2-1 x->1 I am saying that this limit does not exist because of the 0 numberator. In this one, I have forgotten the rules for square roots. lim [(sq rt 2x-1) -3]/x-5 x->5-
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Originally Posted by becky Just need a couple of problems double checked for me. lim (x^2+4x-5)/x^2-1 x->1 You have, Express as, Which cancels,
Originally Posted by becky lim [(sq rt 2x-1) -3]/x-5 x->5- You have, Rationalize numerator, Thus, Thus, Thus, ---------------- Basic rule, is that if you have a fraction that does not lead to division by zero upon substitution then you can substitute.
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