Just need a couple of problems double checked for me.

lim (x^2+4x-5)/x^2-1

x->1

I am saying that this limit does not exist because of the 0 numberator.

In this one, I have forgotten the rules for square roots.

lim [(sq rt 2x-1) -3]/x-5

x->5-

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- April 3rd 2006, 06:37 PMbeckyLimits
Just need a couple of problems double checked for me.

lim (x^2+4x-5)/x^2-1

x->1

I am saying that this limit does not exist because of the 0 numberator.

In this one, I have forgotten the rules for square roots.

lim [(sq rt 2x-1) -3]/x-5

x->5- - April 3rd 2006, 06:57 PMThePerfectHackerQuote:

Originally Posted by**becky**

Express as,

Which cancels,

- April 3rd 2006, 07:03 PMThePerfectHackerQuote:

Originally Posted by**becky**

Rationalize numerator,

Thus,

Thus,

Thus,

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Basic rule, is that if you have a fraction that does not lead to division by zero upon substitution then you can substitute.