The Eq is supposed to be solved for Y as a function of X : $\displaystyle y^x = x^y + 1$
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Originally Posted by xterminal01 The Eq is supposed to be solved for Y as a function of X : $\displaystyle y^x = x^y + 1$ Take the natural log of both sides... $\displaystyle xln|y|=yln|x|$ $\displaystyle \frac{y}{x}=\frac{ln|y|}{ln|x|}$ $\displaystyle \frac{y}{x}=log_xy$ I'm now as lost as you are...
Recall $\displaystyle \log(a+b)$ has not property.
Set $\displaystyle g(x,y)=y^{x}-x^{y}-1$ $\displaystyle \frac{\partial{g}}{\partial{y}}=xy^{x-1}-x^{y}\ln(x),$ whose value at (1,2) equals 1 ? Is this correct?
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