The Eq is supposed to be solved for Y as a function of X :

$\displaystyle y^x = x^y + 1$

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- Dec 7th 2007, 10:26 AMxterminal01Solve for y as a function of x
The Eq is supposed to be solved for Y as a function of X :

$\displaystyle y^x = x^y + 1$ - Dec 7th 2007, 11:24 AMcolby2152
- Dec 7th 2007, 11:29 AMKrizalid
Recall $\displaystyle \log(a+b)$ has not property.

- Dec 7th 2007, 01:12 PMxterminal01
Set $\displaystyle g(x,y)=y^{x}-x^{y}-1$

$\displaystyle \frac{\partial{g}}{\partial{y}}=xy^{x-1}-x^{y}\ln(x),$

whose value at (1,2) equals 1 ? Is this correct?