How to integrate the equation below? thx i am confused and my brain is filled with murky glue!:((

(secx+tanx)dx (sorry the front symbol i dont know how to type in)

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- Dec 7th 2007, 01:21 AMDream is not UtopiaConfused by integration!
How to integrate the equation below? thx i am confused and my brain is filled with murky glue!:((

(secx+tanx)dx (sorry the front symbol i dont know how to type in) - Dec 7th 2007, 03:10 AMKrizalid
Since you have a sum, integrate each term separately:

$\displaystyle \int {\sec x\,dx} = \int {\sec x \cdot \frac{{\sec x + \tan x}}

{{\sec x + \tan x}}\,dx} .$

And for the another piece $\displaystyle \int {\tan x\,dx} = \int {\frac{{\sin x}}

{{\cos x}}\,dx} = - \int {\frac{{(\cos x)'}}

{{\cos x}}\,dx} .$ - Dec 7th 2007, 04:52 AMcolby2152
$\displaystyle \int sec(x)+tan(x)dx = \int \frac{1+sin(x)}{cos(x)}dx$

A good way to start with these is to put everything into sines and cosines.