Hello, polymerase!
If , find the value of
Choices: .
I agree with your answer . . .
.??
The function does not exist at that point, so neither does its derivative.
If , find the value of
Choices:
a)
b)undefined
c)
d)
e)
alright, heres where im at right now:
1)It could be undefined because is not in the domain of f(x)?
2)the answer is and my prof made a mistake(seems unlikely since he's been doing this for 20 years)?
3)my friend says its ?
Can anyone confirm which is correct with justification?
Thanks!
Hello, I did this and used Maple to confirm. Finding the derivative of this double ln first:
ln(ln(x)) = 1/ln(x) * 1/x
now you sub in (1/e)
1/ln(1/e) = 1/ln(e^-1) noting that.. ln (e^x) = x
so = 1/ln(e^-1) = 1/-1 * 1/(1/e)
so multiply the reciprical since your dividing by a fraction and your final answer is -e!
Im pretty sure im right, and im matching the answer of your 20 years experience prof :P