# continuous function proof

• Dec 5th 2007, 11:50 AM
chrisc
continuous function proof
Suppose that f(x) is any function that is continuous at x=0.
Prove that the function g(x) = xf(x) is differentiable at x=0.

Now my first instinct was to say that this cannot be done.
If a function is continuous at a certain value of x does not mean its differentiable at that point as well.

Can someone shed some light here.

Maybe the question intends for the function to be differentiable at (x) as well.
• Dec 5th 2007, 12:09 PM
Opalg
Go back to the definition: g(x) is differentiable at 0 if $\lim_{h\to0}\frac{g(h)-g(0)}h$ exists. So, does that limit exist, or not?
• Dec 5th 2007, 12:24 PM
colby2152
Quote:

Maybe the question intends for the function to be differentiable at (x) as well.
Probably, because continuity doesn't imply differentiability. However, if you can take a derivative at a point, then it does mean the function is continuous at that point.
• Dec 5th 2007, 12:26 PM
chrisc
it could, depending on the function

|x| for example