could do with some help please
find stationary points y= 2√x - x
thanks
As colby2152 says, take the first derivative
$\displaystyle y^{\prime} = \frac{1}{\sqrt{x}} - 1$
and set it to 0:
$\displaystyle \frac{1}{\sqrt{x}} - 1 = 0$ <-- Multiply both sides by $\displaystyle \sqrt{x}$
$\displaystyle 1 - \sqrt{x} = 0$
You should be able to take it from here.
-Dan