Find the dy/dx. arcsin ( ) I got This, is not correct, I used the typical trig formula for this. 1/(1-u^2) * du/dx. Thanks!
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Originally Posted by Truthbetold Find the dy/dx. arcsin ( ) I got This, is not correct, I used the typical trig formula for this. 1/(1-u^2) * du/dx. Thanks! now how in the world did you end up with t in your answer? where is a function of now, if , what is ?
Originally Posted by Jhevon now how in the world did you end up with t in your answer? where is a function of now, if , what is ? I don't know how I got t in my answer. I made a typo. Derivative of u'=
Originally Posted by Truthbetold I don't know how I got t in my answer. I made a typo. Derivative of u'= ok, so now try again. what's the derivative of the original function?
.. my answer
Originally Posted by Truthbetold .. my answer that is correct. you could simplify it, but that's fine
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