Find the dy/dx.

arcsin ($\displaystyle \sqrt{x}$)

I got $\displaystyle \frac{\sqrt{x}}{\sqrt{1-2t}}$

This, is not correct,

I used the typical trig formula for this. 1/(1-u^2) * du/dx.

Thanks!

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- Dec 3rd 2007, 10:45 PMTruthbetoldInverse Trigonmetric functions
Find the dy/dx.

arcsin ($\displaystyle \sqrt{x}$)

I got $\displaystyle \frac{\sqrt{x}}{\sqrt{1-2t}}$

This, is not correct,

I used the typical trig formula for this. 1/(1-u^2) * du/dx.

Thanks! - Dec 3rd 2007, 10:58 PMJhevon
- Dec 3rd 2007, 11:12 PMTruthbetold
- Dec 3rd 2007, 11:14 PMJhevon
- Dec 3rd 2007, 11:27 PMTruthbetold
$\displaystyle \frac{1}{2\sqrt{x} * \sqrt{1-x}}$.. my answer

- Dec 3rd 2007, 11:28 PMJhevon