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Math Help - Solving an integral by substitution (two questions)

  1. #16
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by angel.white View Post
    I got 74/80 = 92.5%
    ...
    But then my instructor curved it, so the grade on the books is out of 74
    Nice!
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  2. #17
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    Error in limits

    ebonyscythe, I think you have an error in the limits of your first integral:
    u = \cos x, so when x=0, u = \cos (0) = 1, and so your first integral should be -\int_{1}^{-1} u^2*du, not -\int_{0}^{-1} u^2*du.


    --Kevin C.
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