# Solving an integral by substitution (two questions)

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• Dec 4th 2007, 12:31 PM
Jhevon
Quote:

Originally Posted by angel.white
:) I got 74/80 = 92.5%
...
But then my instructor curved it, so the grade on the books is out of 74 ;)

Nice!
• Dec 4th 2007, 04:05 PM
TwistedOne151
Error in limits
ebonyscythe, I think you have an error in the limits of your first integral:
$u = \cos x$, so when x=0, $u = \cos (0) = 1$, and so your first integral should be $-\int_{1}^{-1} u^2*du$, not $-\int_{0}^{-1} u^2*du$.

--Kevin C.
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