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Math Help - Polar Equation from Cartesian

  1. #1
    Junior Member
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    Polar Equation from Cartesian

    Find a polar equation for the curve represented by the given Cartesian equation.

    1. x^2 - y^2 = 1

    so I know x = rcos(-) , y = rsin(-)

    [rcos(-)]^2 - [rsin(-)]^2 = 1

    r^2[ (cos(-))^2 - (sin(-))^2 ) = 1

    r^2 [ cos2(-) ] = 1

    ??
    can someone show me how to do this.. am i doing this completely wrong? lol thanks..
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  2. #2
    Member Henderson's Avatar
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    Looks great!

    Often you'll see polar equations solved for r in terms of theta, but what you've done is perfect so far.
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