Looks great!
Often you'll see polar equations solved for r in terms of theta, but what you've done is perfect so far.
Find a polar equation for the curve represented by the given Cartesian equation.
1. x^2 - y^2 = 1
so I know x = rcos(-) , y = rsin(-)
[rcos(-)]^2 - [rsin(-)]^2 = 1
r^2[ (cos(-))^2 - (sin(-))^2 ) = 1
r^2 [ cos2(-) ] = 1
??
can someone show me how to do this.. am i doing this completely wrong? lol thanks..