The line must satisfy f(2) = 1, so the slope and y-intercept will vary. We want the minimum area.

with ,

and

Therefore...

We want to minimize the area of the 1st quadrant or the area of y-intercept * x-intercept

The x-intercept is when y=0

The y-intercept is just b

b = 1-2m

Area must be equal to:

Find the derivative and set equal to zero...

Slope must equal -0.5 since a positive slope will give an infinite area in the 1st quadrant...

AREA: