Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region. From (5/3) to (25/3) 3x^2-5x dx I keep getting 407.40737 and it's not right! I dunno what I am doing wrong! BAH!
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Originally Posted by MathNeedy18 Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region. From (5/3) to (25/3) 3x^2-5x dx I keep getting 407.40737 and it's not right! I dunno what I am doing wrong! BAH! Hello, first calculate the intercepts of the two functions: (0, 0), (5/3, 25/3) The enclosed area is calculated by the difference of the two functions: I'm sure that you can do the rest. (For confirmation only: )
So first you need to find the points of intersection: (0,0) and (5/3,25/3). Then you can integrate with respect to x. Make sure you take the function on top 5x and subtract the lower function 3x^2. I get 125/54.
omg! Thanks! I made the dumbest mistakes! I was finding it from 25/3 to 5/3 instead of 0 to 5/3!!!
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