Find an equation for the plane consisting of all points that are equidistant from the points (-4,2,1) and (2,-4,3)
can someone show me how this is done?
what is equidistant..?
thanks for any help
The midpoint of the line segment determined by those points is (-1,-1,2).
The vector determined is <6,-6,2>.
Use the vector <3,-3,1> as the normal to write the equation of the plane containing (-1,-1,2).