Let me resume with this. Let be at least a degree two polynomial with zeros of multiplicity 1 having no real zeros. Thus, it has to be a degree even polynomial because odd degree polynomials have real zeros. Let be its complex zeros. Since they occur in conjugate pairs half of them are in the upper plane and half of them in the lower plane. Rename these zeros so that are in the upper plane. Now the polynomial can be written as . By step #4 in the above post we have so we need to compute and evaluate that expression (after it is simplified) at for . Thus, we need to find, . That can seem like it is hard to compute but note that by applying the generalized product rule. Thus, the value for in step #4 is . Thus, by step #5 the total sum is .

And we therefore have that: .

Try for example: .