Evaluate

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- December 1st 2007, 06:03 PMliyiIntegral with square root
Evaluate

- December 1st 2007, 06:22 PMJhevon
the easy way: you could realize that this integral gives you the area of the upper half of the circle with radius 8

the hard way: use the trig substitution ....since we have an even function here, you may also wish to change the problem to , and change the limits based on the trig substitution