Can someone please help me derivate this
$\displaystyle h(x)=(x+1)^2(2x+1)^3 $
Thank you!
Thank you for your reply!
I do know the product rule in case you are talking about the uv´+vu´ rule, where the accent indicates derivated(I am sorry, I am very bad at these terms, since the textbook we are using is in Finnish). However, whenever I try to apply this rule, I get the wrong answer. Here is what I did.
$\displaystyle (X+1)^3*2(2X-1)^1+ (2X-1)^2*3(X+1)^2 $
Yes, that states the product rule. (Don't worry about the terms, I'm chilean and I have to learn them anyway.)
$\displaystyle \Big[ {f(x) \cdot g(x)} \Big]' = f'(x) \cdot g(x) + f(x) \cdot g'(x).$
The function is $\displaystyle h(x)=(x+1)^2(2x+1)^3,$
So $\displaystyle h'(x)=2(x+1)\cdot(2x+1)^3+3(x+1)^2(2x+1)^2\cdot2.$
Can you take it from there?