$\displaystyle y=[sin(x+5)]^1.25$
Find the derivative.
I got {5/4 sin(x+5)cos(x+5)}^(1/4).
I don't think that's right.
Thanks!
Hello, Truthbetold!
Be careful with the Chain Rule . . .
Differentiate: .$\displaystyle y\:=\:[\sin(x+5)]^{\frac{5}{4}}$
. . $\displaystyle \frac{dy}{dx} \;=\;\overbrace{\frac{5}{4}\!\cdot[\sin(x+5)]^{\frac{1}{4}}}^{\text{diff. power}}\cdot\overbrace{\cos(x+5)}^{\text{diff. }\sin}\cdot \overbrace{1}^{\text{diff. }x+5}$