if anybody could help with this that would be much appreciated:
Find the point on the graph f(x)=4/3x^3 where the tangent line is perpendicular to the line y=-16x+3
Thanks in advance
-Ryan
Remember two lines are perpendicular to one another if and only if their slopes are negative reciprocals of each other.Originally Posted by compuryan
Thus, means the perpendicular line has slope .
The slope of any given point on the graph is its derivative which is,
.
We need that to be as explained in the first paragraph thus, . Solving we have that . These are the two x-values on the graph where the tangent is perpendicular to this line.