if anybody could help with this that would be much appreciated:

Find the point on the graph f(x)=4/3x^3 where the tangent line is perpendicular to the line y=-16x+3

Thanks in advance

-Ryan

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- Mar 28th 2006, 01:29 PMcompuryanTangent Line
if anybody could help with this that would be much appreciated:

Find the point on the graph f(x)=4/3x^3 where the tangent line is perpendicular to the line y=-16x+3

Thanks in advance

-Ryan - Mar 28th 2006, 06:24 PMThePerfectHackerQuote:

Originally Posted by**compuryan**

Thus, means the perpendicular line has slope .

The slope of any given point on the graph is its derivative which is,

.

We need that to be as explained in the first paragraph thus, . Solving we have that . These are the two x-values on the graph where the tangent is perpendicular to this line.