Can someone pls tell me what the x partial derivative of:
(25-(x^2)-(y^2))^(1/2) is and how you would go about working it out.
Let me just post the answer so you can check with mine.Originally Posted by jedoob
$\displaystyle z=\sqrt{25-x^2-y^2}$ consider $\displaystyle y$ a constant because you need to find $\displaystyle \frac{\partial z}{\partial x}$.
Thus, by the chain rule,
$\displaystyle \frac{1}{2}\cdot (-2x)(25-x^2-y^2)^{-1/2}$
Thus,
$\displaystyle -\frac{x}{\sqrt{25-(x^2+y^2)}}$