Can someone pls tell me what the x partial derivative of:

(25-(x^2)-(y^2))^(1/2) is and how you would go about working it out.

Printable View

- Mar 28th 2006, 11:27 AMjedoobpartial derivative
Can someone pls tell me what the x partial derivative of:

(25-(x^2)-(y^2))^(1/2) is and how you would go about working it out. - Mar 28th 2006, 11:36 AMjedooball ok
it's ok - i worked it out.

- Mar 28th 2006, 11:46 AMTD!
Are you sure? If you want we can check your answer if you post it :)

- Mar 28th 2006, 06:49 PMThePerfectHackerQuote:

Originally Posted by**jedoob**

$\displaystyle z=\sqrt{25-x^2-y^2}$ consider $\displaystyle y$ a constant because you need to find $\displaystyle \frac{\partial z}{\partial x}$.

Thus, by the chain rule,

$\displaystyle \frac{1}{2}\cdot (-2x)(25-x^2-y^2)^{-1/2}$

Thus,

$\displaystyle -\frac{x}{\sqrt{25-(x^2+y^2)}}$