Need Help!!

**mathlete** · November 28th 2007, 10:46 AM

Write an expression for the function, g(x), if it is known that g '(x) = sin(x)/x and g(3) = 7.

Give your answer using the form below.

C =
a =
A(t) =

can i get someone to help me with this one...show me what do to...thanks...

mathlete

**Plato** · November 28th 2007, 10:57 AM

Here is one possible solution.
$\begin{array}{l} C = 7 \\ a = 3 \\ A(t) = \frac{{\sin (t)}}{t} \\ \end{array}$

Do you understand why?

**mathlete** · November 28th 2007, 11:27 AM

Originally Posted by Plato

Here is one possible solution.
$\begin{array}{l} C = 7 \\ a = 3 \\ A(t) = \frac{{\sin (t)}}{t} \\ \end{array}$

Do you understand why?

not quite, i understand the A(t), but how do you figure that the other values are just the ones given in the problem?

**Plato** · November 28th 2007, 12:06 PM

Originally Posted by mathlete

how do you figure that the other values are just the ones given in the problem?

They happen to work!
Don't they work?
Lets see, g(3)=7. Do you see why?

$g(x) = \int\limits_a^x {f(t)dt} + C\quad \Rightarrow \quad g(a) = C$

Thread: Need Help!!