Originally Posted by

**coe236** *A charged particle moves along the x-axis under the influence of an electric field. The field strength varies with time, and as a result, the velocity of the particle is complicated. The position of the particle at time t is written as x=x(t) and the velocity of the particle at time t is written as v(t).*

*Suppose we know that x(0)=0, and also that*

*v(t)={2t-1, if 0*__<__t__<__1

*{4t-3, if 1*__<__t__<__2

*{6t-7, if 2*__<__t__<__3

*What is x(1)? (...find x(2), x(3) and sketch x=x(t), v=v(t))*

So, obviously we can take the antiderivative of v(t) to find x(t) from which you get: $\displaystyle t^2-t+C, 2*t^2-3*t+C, 3*t^2-7*t+C$ ..whats confusing me is the three different intervals for time t. how do i solve for x(1) if there are 2 different antiderivatives for it?? Im confused