Find the slope and the equation of the tangent line to the function f(x)=x^2+3x+2 at x=1. My answer: 3 1x+3x+2=6x f(x) -f(1)/x(-1)=3 Is that right??
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Originally Posted by batman123 Find the slope and the equation of the tangent line to the function f(x)=x^2+3x+2 at x=1. My answer: 3 1x+3x+2=6x f(x) -f(1)/x(-1)=3 Is that right?? Slope is the derivative evaluated at thus, thus, Thus, slope is 5. ------- To find equation use the formula, where is a point. Notice if then, Thus, Solve for thus,
thank you I see what I did wrong.
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