Find the slope and the equation of the tangent line to the function f(x)=x^2+3x+2 at x=1.

My answer: 3

1x+3x+2=6x

f(x) -f(1)/x(-1)=3

Is that right?? :confused:

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- March 26th 2006, 03:39 PMbatman123Checking Tangent
Find the slope and the equation of the tangent line to the function f(x)=x^2+3x+2 at x=1.

My answer: 3

1x+3x+2=6x

f(x) -f(1)/x(-1)=3

Is that right?? :confused: - March 26th 2006, 03:45 PMThePerfectHackerQuote:

Originally Posted by**batman123**

thus,

thus,

Thus, slope is 5.

-------

To find equation use the formula,

where is a point.

Notice if then,

Thus,

Solve for thus,

- March 26th 2006, 04:16 PMbatman123Thanks
thank you I see what I did wrong.