integral involving absoulte value
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When dealing with an absolute value, it usually helps to break it into two integrals. But the region is symmetric, so just multiply by two $\displaystyle 2\int_{3}^{4}(x-3)dx$
Last edited by galactus; Nov 24th 2008 at 05:38 AM.
thank you for the very nice sketch. after reviewing your suggestions, am I correct in saying that the integral equates to 1.
Hello, DINOCALC09! If you make a sketch, you don't need Calculus! $\displaystyle \int^4_2|x - 3|\,dx$ Code: | \ | \ | \ | \ / | \ / | \ / | \ / | |:\ /:| | |:::\ /:::| - + - - + - - + - - * - - + - - + - - 1 2 3 4 5 Got it?
| \ | \ | \ | \ / | \ / | \ / | \ / | |:\ /:| | |:::\ /:::| - + - - + - - + - - * - - + - - + - - 1 2 3 4 5
i just find the area of the two triangles. correct?
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