I need help with this question. How would you do something like this (below)? I know that the derivative of a function at a point equals the slope of the tangent line to the graph of the function at that particular point, but the derivative comes out to be a quadratic. Please help. Thanks.

Let the function $\displaystyle f$ be given by $\displaystyle f(x)=x^3+2x-8x+3$. Write an equation of the line tangent to the graph of $\displaystyle f$ at $\displaystyle x=-2$.