# Derivative help using Square Root

• Mar 26th 2006, 12:43 PM
wild_flowr69
Derivative help using Square Root
F(x)=2√x + 3 3√x
• Mar 26th 2006, 12:48 PM
TD!
If you know that a square root is the same as a power 1/2, then you can just apply the power/exponent rule.
• Mar 26th 2006, 01:35 PM
ThePerfectHacker
Quote:

Originally Posted by wild_flowr69
F(x)=2√x + 3 3√x

$2\sqrt{x}+3\sqrt[3]{x}$
$2x^{1/2}+3x^{1/3}$
$x^{-1/2}+x^{-2/3}$
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