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Math Help - derivative

  1. #1
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    derivative

    h(x)=2 squarex + 3 3 square x


    k(t)= 8t 3/2

    g(x) 6x^5-4x^3+x^2
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  2. #2
    TD!
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    And the question is, find the derivative?
    Do you know the different rules and if so, what is the problem?
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  3. #3
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    Quote Originally Posted by batman123
    g(x) 6x^5-4x^3+x^2
    I do not understand the first two problems, they are dreadfully ambigous.

    Given,
    6x^5-4x^3+x^2
    You need to find, (the derivative)
    (6x^5-4x^3+x^2)'
    thus, by the sum-rule,
    (6x^5)'-(4x^3)'+(x^2)'
    thus, by the constant-multiple rule,
    6(x^5)'-4(x^3)'+(x^2)'
    thus, by the power-rule,
    6(5x^4)-4(3x^2)+(2x)
    thus, after some algebra,
    30x^4-12x^2+2x

    \left<\begin{array}{ccc}\mathbb{Q}&\,&\, \\ \,& \mathbb{E}&\, \\ \,&\,&\mathbb{D} \end{array}\right>
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