derivative

**batman123** · March 25th 2006, 01:45 PM

h(x)=2 squarex + 3 3 square x

k(t)= 8t 3/2

g(x) 6x^5-4x^3+x^2

**TD!** · March 25th 2006, 01:48 PM

And the question is, find the derivative?
Do you know the different rules and if so, what is the problem?

**ThePerfectHacker** · March 25th 2006, 04:02 PM

Originally Posted by batman123

g(x) 6x^5-4x^3+x^2

I do not understand the first two problems, they are dreadfully ambigous.

Given,
$6x^5-4x^3+x^2$
You need to find, (the derivative)
$(6x^5-4x^3+x^2)'$
thus, by the sum-rule,
$(6x^5)'-(4x^3)'+(x^2)'$
thus, by the constant-multiple rule,
$6(x^5)'-4(x^3)'+(x^2)'$
thus, by the power-rule,
$6(5x^4)-4(3x^2)+(2x)$
thus, after some algebra,
$30x^4-12x^2+2x$

$\left<\begin{array}{ccc}\mathbb{Q}&\,&\, \\ \,& \mathbb{E}&\, \\ \,&\,&\mathbb{D} \end{array}\right>$

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