h(x)=2 squarex + 3 3 square x
k(t)= 8t 3/2
g(x) 6x^5-4x^3+x^2
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h(x)=2 squarex + 3 3 square x
k(t)= 8t 3/2
g(x) 6x^5-4x^3+x^2
And the question is, find the derivative?
Do you know the different rules and if so, what is the problem?
I do not understand the first two problems, they are dreadfully ambigous.Quote:
Originally Posted by batman123
Given,
$\displaystyle 6x^5-4x^3+x^2$
You need to find, (the derivative)
$\displaystyle (6x^5-4x^3+x^2)'$
thus, by the sum-rule,
$\displaystyle (6x^5)'-(4x^3)'+(x^2)'$
thus, by the constant-multiple rule,
$\displaystyle 6(x^5)'-4(x^3)'+(x^2)'$
thus, by the power-rule,
$\displaystyle 6(5x^4)-4(3x^2)+(2x)$
thus, after some algebra,
$\displaystyle 30x^4-12x^2+2x$
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