$\displaystyle dx/(2x+7)$ limits are from 2 to 0. The only one on my homework I cannot get...any help would be appreciated.
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Originally Posted by calculuslyfrustrated $\displaystyle dx/(2x+7)$ limits are from 2 to 0. What's the matter? Note that $\displaystyle \int_2^0 {\frac{1} {{2x + 7}}\,dx} = \frac{1} {2}\int_2^0 {\frac{{(2x + 7)'}} {{2x + 7}}\,dx} = \frac{1} {2}\left( {\ln \left| {2x + 7} \right|\Big|_2^0} \right).$ You may go on from there.
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