Find dy/dx I don't know how to work with . I used the chain rule twice and got . That, however, is not the correct answer. It is . Thanks!
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Originally Posted by Truthbetold Find dy/dx I don't know how to work with . I used the chain rule twice and got . That, however, is not the correct answer. It is . Thanks! your answer is way off. the correct answer is not readily apparent, you have to apply a trig identity to get it in the required form. the trick is to think of as so, ..............by the chain rule now recall the identity, , thus we have: as desired
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