Let b>a>0, k be any real number except -1. Show that the area A of the region bounded by y=x^k, Y=0,x=a,x=b is A=[b^(k+1)-a^(k+1)]/(k+1) square units

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- Aug 8th 2014, 09:03 AM #1

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- Aug 8th 2014, 09:53 AM #2

- Aug 8th 2014, 07:16 PM #3

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## Re: Hello!

i know. But i have to be compeled different way. In solution, Let t=(b/a)^(1/n)b and x0=a, x1=at, x2=a(t^2),..., xn=a(t^n)=b

Use Area of R= lim Sn (n to infinite) , Delta xi=(b-a)/n and xi=a+i*delta x

Sn= f(x1)*delta(x1)+ . . .f(xn)*delta(xn). YOU KNOW THIS WAY

- Aug 8th 2014, 07:30 PM #4

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