1. ## Midpoint Rule Problem

$\displaystyle \int_{0}^{1}13\cos(x)^{2} dx$

n = 4

values of intervals

are $\displaystyle y_{0} = 13$

$\displaystyle y_{1} = 12.9997525$

$\displaystyle y_{2} = 12.99901002$

$\displaystyle y_{3} = 12.99777261$

$\displaystyle y_{4} = 12.996040$

change in $\displaystyle x = \dfrac{b - a}{n} = \dfrac{1 - 0}{4} = 1/4$

Midpoint Rule

2. ## Re: Midpoint Rule Problem

First, like we have said in the other post, use radians lol.
Also, although the partition is 0, 0.25, 0.5, 0.75, 1, midpoint rule requires you to find f(0.125), f(0.375), f(0.625) and f(0.875).
Add them up and multiply by the partition width - 0.25.