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Math Help - Finding Equation of Tangent Line (Parametric)

  1. #1
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    Finding Equation of Tangent Line (Parametric)

    (3,2)

    (y - 2) = m(x - 3)

    x = 3 + \ln t

    y = t^{2} + 1

    m = \dfrac{dy/dt}{dx/dt} = \dfrac{2t}{1/t} = 2t^{2}

    Finding t

    3 = 3 + \ln t

    0 = \ln t

    1 = t

    m = 2(1)^{2} = 2

    (y - 2) = 2(x - 3)

    (y - 2) = 2x - 6

    y = 2x - 4

    I think this is right.
    Last edited by Jason76; July 26th 2014 at 12:02 AM.
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  2. #2
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    Re: Finding Equation of Tangent Line (Parametric)

    That is correct
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