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Thread: Finding Equation of Tangent Line (Parametric)

  1. #1
    MHF Contributor Jason76's Avatar
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    Finding Equation of Tangent Line (Parametric)

    $\displaystyle (3,2) $

    $\displaystyle (y - 2) = m(x - 3) $

    $\displaystyle x = 3 + \ln t $

    $\displaystyle y = t^{2} + 1 $

    $\displaystyle m = \dfrac{dy/dt}{dx/dt} = \dfrac{2t}{1/t} = 2t^{2} $

    Finding t

    $\displaystyle 3 = 3 + \ln t $

    $\displaystyle 0 = \ln t $

    $\displaystyle 1 = t $

    $\displaystyle m = 2(1)^{2} = 2$

    $\displaystyle (y - 2) = 2(x - 3) $

    $\displaystyle (y - 2) = 2x - 6 $

    $\displaystyle y = 2x - 4$

    I think this is right.
    Last edited by Jason76; Jul 26th 2014 at 12:02 AM.
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  2. #2
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    Re: Finding Equation of Tangent Line (Parametric)

    That is correct
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