1. ## Parametric Application

If a projectile is fired with an initial velocity of v0 meters per second at an angle α above the horizontal and air resistance is assumed to be negligible, then its position after t seconds is given by the parametric equations

$x = (v_{0}\cos\theta)t$

$y = (v_{0}(\sin\theta)t =- \dfrac{1}{2}gt^{2}$

where g is the acceleration due to gravity (9.8 m/s2). (Round your answers to the nearest whole number.) (a) If a gun is fired with α = 30° and v0 = 900 m/s.

$x = (900 m/s\cos30^{o})t$

$y = (900 m/s\sin30^{o})t =- \dfrac{1}{2}(9.8 m/s)t^{2}$

$x = (900 m/s\dfrac{\sqrt{3}}{2})t$

$y = (900 m/s\dfrac{1}{2})t - \dfrac{1}{2}(9.8 m/s)t^{2}$

When will the bullet hit the ground?

$(900 \dfrac{1}{2})t - \dfrac{1}{2}(9.8)t^{2} = 0$

$300t - 4.9t^{2} = 0$

$t(300 - 4.9t) = 0$

$t = 0s$

$t = 61.2s$

How far from the gun will it hit the ground?

$t = \dfrac{300}{4.9} = 61$

What is the maximum height reached by the bullet?

(b) Find the equation of the parabolic path by eliminating the parameter.

2. ## Re: Parametric Application

No idea what is going on here.