# Math Help - Question regarding delta-epsion proof

1. ## Question regarding delta-epsion proof

Why is this sign, that I highlighted in yellow, changes to the equal sign? Sevens just cancel, why would something else have to happen? Also, we are proving that this expression we started with in our proof is less than $\epsilon$ as we show in the subsequent statement and not equal.

2. ## Re: Question regarding delta-epsion proof

The overall inequality you need still holds.

They are just saying that $7(\epsilon/7)=\epsilon$ which as you note is obvious.

The < sign on the line above still causes $|(7x-1)-27|<\epsilon$

3. ## Re: Question regarding delta-epsion proof

Oh, I think I got it. So they are just explicitly noting that we have this sign <, but the actual quantity after this sign is going to equal to $\epsilon$ hence this equality sign.