$\sum_{k=1}^{\infty} \frac{(-3)^{k+1}}{4^{2k}}$
$\sum_{m=1}^{\infty} (\sqrt[m]{3}-1)^m$
Help!
I suppose the 2nd one requires root test: Pauls Online Notes : Calculus II - Root Test
As m approaches infinity, the limit of the mth root of the sequence will approach 0. Since it's less than 1, the series converges. Correct me if I'm wrong though.