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Thread: Indefinite Integral

  1. November 19th 2007, 09:44 AM #1
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    Indefinite Integral




    I've tried this so many times and I can't seem to find the right answer, please help.
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  2. November 19th 2007, 09:45 AM #2
    Krizalid
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    All you need to set it is u=\sqrt{36x^2-1}.
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  3. November 19th 2007, 10:04 AM #3
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    What would du be in that case?
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  4. November 19th 2007, 10:56 AM #4
    Krizalid
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    du=\frac{36x}{\sqrt{36x^2-1}}\,dx.
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