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Math Help - Indefinite Integral

  1. #1
    Del
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    Indefinite Integral




    I've tried this so many times and I can't seem to find the right answer, please help.
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  2. #2
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    All you need to set it is u=\sqrt{36x^2-1}.
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  3. #3
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    What would du be in that case?
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  4. #4
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    du=\frac{36x}{\sqrt{36x^2-1}}\,dx.
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