If f(x) = (2+3x)^4, then find the 4th derivative of f(x). A. 0 B. 4!(3) C. 4!(3^4) D. 4!(3^5) E. 4!(2+3x)
Follow Math Help Forum on Facebook and Google+
Originally Posted by DINOCALC09 If f(x) = (2+3x)^4, then find the 4th derivative of f(x). A. 0 B. 4!(3) C. 4!(3^4) D. 4!(3^5) E. 4!(2+3x) C. think about it, why is that? (you don't have to actually find the fourth derivative explicitly, you can think through it)
there are 4 powers so that wil cross out making it 0 which is letter A? correct?
Originally Posted by DINOCALC09 there are 4 powers so that wil cross out making it 0 which is letter A? correct? no, i told you the answer is C.
f(x) = (2+3x)^4 is it something to do with losing the x making it 3^4?? i dont know
Originally Posted by DINOCALC09 If f(x) = (2+3x)^4, then find the 4th derivative of f(x). A. 0 B. 4!(3) C. 4!(3^4) D. 4!(3^5) E. 4!(2+3x) $\displaystyle f'(x)=4\cdot3(2+3x)^3.$ So we'll have $\displaystyle 4!$ on the final expression and by the chain rule, $\displaystyle 3^4,$ can you see that?
View Tag Cloud