I'm getting lost in the algebra. Can somebody please help me!

I'm trying to get a derivitive of:

x(x^2-6x+16)/(x-2)^3

I've gotten this far:

(x-2)^3(2x-6)-(x^2-6x+16)3(x-2)/((x-2)^2)^3

This is where I get lost.

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- Nov 19th 2007, 10:01 AMstanger4joNeed help with a derivitive problem
I'm getting lost in the algebra. Can somebody please help me!

I'm trying to get a derivitive of:

x(x^2-6x+16)/(x-2)^3

I've gotten this far:

(x-2)^3(2x-6)-(x^2-6x+16)3(x-2)/((x-2)^2)^3

This is where I get lost. - Nov 19th 2007, 11:56 AMPeritus
no need to get lost, the important thing is to bring the expression to a convenient form:

f(x) = x(x^2-6x+16)/(x-2)^3 = (x^3 - 6x^2 + 16x) / (x-2)^3 =

= (x^3 -6x^2 + 16x)*(x-2)^-3

now as you know d/dx(a(x)*b(x)) = a '(x)*b(x) + a(x)*b '(x)

in the present case a(x) = (x^3 -6x^2 + 16x) , b(x) = (x-2)^-3

f '(x) = (3x^2-12x+16)/(x-2)^3 -3*(x^3 - 6x^2 + 16x)/(x-2)^4 - Nov 19th 2007, 02:46 PMstanger4jo
Thank you so much for your help. I think I've got it now.:)