i was able to wake up early.. Ü

let us try solving the general case:

consider the operator , then we can transform the equation into , where (i have to change our variable to y because we need the imaginary number ).

so,

but the middle one is also equal to

also using similar arguments, it can be shown that

if we take and , then we have the general solution:

---> 1

now, to solve for the value of and , just consider that

equate equation 1 to 0.

solve for the first derivative of that equation 1 and equate to 0..

now you have two equations with two unknowns .. can you contnue it?

i'm late for my class...