Basic Calculus HELP!!!!!!!! (:-)

Find the gradient of the tangeant to the curve:

$\displaystyle

f(x) = x^3/2 - 5x^2$ at $\displaystyle x = 2$

Find the coordinates of the points at the curve:

$\displaystyle f(x) = (3x - 2)^2 $ at which the tangeant is parralel to the line y - 6x = 8.

Find the coordinates of the points on the curve $\displaystyle y = x^3 - x^2 + 5x - 3$ at which the tangeant is perpindicular to $\displaystyle x + 12y = 38$

Find the equation of the curve $\displaystyle y = f(x)$ given $\displaystyle f'(x) = 4x^2 - x + 1$ and $\displaystyle f(0) = 3.$