therefore, they have a unique common point, say (a,b), that satisfies both equation.. so and
if we equate the , we have
this is a quadratic equation hence, we can solve for the value of a:
we want a unique solution for a, so we set the discriminant be equal to 0..
.. solve for k.. Ü
since "hypotenuse" came, it can be assumed that this is a right triangle, hence .. do the algebra..