Alright. So Ill show what Ive tried to do so far and hopefully someone can help me wrap it up. So using 'hospitals rule...
lim sinxlnx
x-> 0+
so I took 2 approaches but came to a halt both ways
FIRST WAY:
lnx/(1/sinx) = FORM infin/infin
so then limit equals
= (1/x)/(-cotx cscx)
dont know where to go from here
SECOND WAY:
sinx/(1/lnx) = FORM 0/0
limit
= cosx/lnx^2
now im stuck again
Yes, this post seems messy.
So, how would I go about fully solving this problem
i guess ill throw this out as well
its the last question Im having trouble with, and my brain is pretty much out of energy
lim ((2x-3)/(2x+5))^(2x+1)
x->infinity
i took the ln of both sides, went to apply lhopitals rule, but no luck.
ended up getting infinity on the top, but not the bottom