A stone is tossed down with a speed of 8m/s from the edge of a cliff 63 m high. how long will it take to hit the foot of the cliff?
vi= 8
a= 9.8
s= 63
i dont know the physics equation for a item being tossed from a cliff.
The stone is subject to gravity. If its initial position height is h(0) and its initial speed v(0), then the equation is:
$\displaystyle h\left( t \right) = h\left( 0 \right) + v\left( 0 \right)t - \frac{{gt^2 }}{2}$.
With g = 9.81 m/sē and h choosen positive in the upwards direction.